Calculate interest and future values in simple interest applications.
Find present value and interest rates in simple interest appliations.
Calculate the interest, principal, and balance portions of amortized loan payments.
Subsection3.2.1Simple Interest
Interest is the term used for the fee charged to borrow money in a loan or the return on a savings account or other investment. Simple interest is calculated as a percentage of the starting amount of the loan or investment.
For example, suppose a college student borrowed $2,000 from their sibling to pay for tuition. They will pay it back after one year with 3% interest. The amount of interest charged will be 3% of $2,000, or \(0.03\cdot2\,000=$60\text{.}\) At the end of the year, the student should pay their sibling the $2,000 borrowed plus $60 in interest.
Interest rates are most-commonly given as annual rates. So, if this student were to repay the money after 3 years, they would owe \(3\cdot60=$180\) in interest. If they were to repay the money after 6 months, which is half of a year, they would owe \(\frac{1}{2}\cdot60=$30\) in interest.
We can generalize to obtain the simple interest formula:
Simple Interest Formula.
\begin{equation*}
I=Prt
\end{equation*}
where
\(I\)
is the interest, which is a dollar amount
\(P\)
is the principal, or starting amount in dollars, also called present value, and
\(r\)
is the annual (yearly) interest rate, which is a percentage expressed in decimal form
t
is the time in years
If the amount of time is given in days, weeks, or months, remember to convert to years before using the formula.
Example3.2.1.
Francesca invested $10,000 in a one-month certificate of deposit account with an annual interest rate of 7%. How much interest will Francesca earn? What will the value of the account be at maturity?
Solution.
First, we convert 1 month to years to find \(t=\frac{1}{12}\text{.}\)
Now we can use the simple interest formula with\(P=10\,000\text{,}\)\(r=0.07\text{,}\) and \(t=\frac{1}{12}\text{,}\) rounding to the nearest cent.
Therefore, Francesca will earn $58.33 in interest, and the value of the account at maturity will be \(10\,000+58.33=$10\,058.33\text{.}\)
With our financial formulas we measure time in years, but the time period for a loan or investment may be given in months or days. In this case, we can still use the simple interest formula, but we need to convert the time period to years before substituting into the formula. For example, since there are 12 months in a year, a time period of 1 month would be \(t=\frac{1}{12}\text{,}\) and a time period of 6 months would be \(t=\frac{6}{12}=\frac{1}{2}\text{.}\) Similarly, since there are 365 days in a year, a time period of 1 day would be \(t=\frac{1}{365}\) and a time period of 31 days would be \(t=\frac{31}{365}\text{.}\)
Example3.2.2.
A payday loan company charges $15 for a 14-day loan of $100. What is the annual interest rate on this loan, assuming simple interest? Round to the nearest hundredth of a percent.
Solution.
We are given the interest \(I=$15\text{,}\) the principal \(P=$100\text{,}\) and the time is 14 days which is \(t=\frac{14}{365}\) years. We need to find the interest rate \(r\text{.}\)
Using the simple interest formula \(I=Prt\text{,}\) we can solve for \(r\text{.}\)
Converting to a percentage and rounding to the nearest hundredth of a percent, we find that the annual interest rate is approximately 391.07%.
Notes:
To find the value of \(r\) on a calculator, we type \(15\div\left(100\times 14 \div 365\right)\) using at set of parentheses around the denominator.
The decimal value of \(r\) is rounded to four places so that the answer will be accurate to two decimal places (the nearest hundredth) after converting to a percentage.
Subsection3.2.2Future Value
We use the term future value to refer to the total value of an account at maturity or the total amount repaid at the end of a simple interest loan. It is the sum of the principal (or present value) and the interest. We typically denote it with the variable \(A\) for amount.
Simple Interest Future Value.
Future value \(A\) can be found using any of these equivalent formulas:
\begin{align*}
A \amp =P+I \\
A \amp =P+Prt \\
A \amp =P(1+rt)
\end{align*}
where \(I\) is the interest amount, \(P\) is the principal or present value, \(r\) is the interest rate in decimal form, and \(t\) is the time in years.
Example3.2.3.
Find the future value of $817 invested at 4.625% simple interest for 8 years.
Solution1.Using \(A=P+I\)
To apply the formula \(A=P+I \text{,}\) we must first calculate the interest \(I\) using the principal \(P=$817\text{,}\) interest rate \(r=0.04625\text{,}\) and time \(t=8\text{.}\)
Which simple interest future value formula should I use? For the most part, you may use any of the three formulas. However, there are some situations where you can make your work easier by selecting the appropriate formula:
Use \(A=P+I\) if you do not know the interest rate or the time.
Use \(A=P+Prt\) if you are solving for the interest rate or the time.
Use \(A=P(1+rt)\) if you are solving for the present value. This formula will be used to derive the compound interest formula in Section 3.4.
Example3.2.4.
What is the present value of $1,500 to be received in 5 years if the annual interest rate is 6% simple interest?
Solution.
To find the present value, we use the formula \(P = A/(1 + rt)\text{,}\) where \(A = 1500\text{,}\)\(r = 0.06\text{,}\) and \(t = 5\text{.}\)
Therefore, the present value is approximately $1,153.85.
This represents the amount that would need to be invested today at 6% simple interest for 5 years in order to have $1,500 at the end of 5 years.
Example3.2.5.
If $275 is invested into an account that earns 7% simple interest, how long will it take for the value to double?
Solution.
We want to find the time \(t\) when the future value \(A\) is double the principal \(P\text{.}\) That is, \(A = 2P\text{.}\) While we do not know the principal, we can still solve for the time because the principal will cancel out in the calculations.
Using the future value formula \(A=P(1+rt)\text{,}\) we can substitute \(2P\) for \(A\) and solve for \(t\text{.}\)
Therefore, it will take approximately 14.29 years for the value to double.
Notice that in the first step, we divided both sides of the equation by \(P\text{,}\) which eliminated the variable \(P\) from the equation.
Subsection3.2.3Amortized Loans
An amortized loan is a loan that is paid off in equal payments over a specified period of time. In each payment, a portion goes toward the interest and the rest goes toward paying down the principal. The interest portion of each payment is calculated using the simple interest formula, and the rest of the payment goes toward reducing the principal or amount owed.
Amortized loans are commonly used for car loans, mortgages, and student loans. The payment amount is calculated so that the loan will be completely paid off at the end of the loan term. This means that the payment amount is based on the original loan amount, the interest rate, and the length of the loan term. We will cover how to calculate the payment amount for an amortized loan in Section 3.5, but for now we will focus on how to calculate the interest and principal portions of each payment and the outstanding balance after each payment.
Example3.2.6.
Find the interest and principal portions of the first payment on a 5-year amortized car loan of $10,000 with an annual interest rate of 6% and monthly payments of $193.33. Then find the outstanding balance after the first payment.
Solution.
First, we find the interest portion of the first payment using the simple interest formula with \(P=$10\,000\text{,}\)\(r=0.06\text{,}\) and \(t=\frac{1}{12}\text{.}\)
For each subsequent payment, the interest is calculated on the remaining balance. This means that the interest portion of each payment will decrease over time as the outstanding balance decreases, while the principal portion will increase over time. By the end of the loan term, the final payment will be mostly principal with very little interest.
An amortization table is a useful tool for keeping track of the interest and principal portions of each payment and the outstanding balance after each payment. It can help you see how much of each payment goes toward interest and how much goes toward paying down the principal over the life of the loan.
Example3.2.7.
Complete an amortization table for the first 3 payments on the car loan in the previous example.
Solution.
We have already found the interest and principal portions of the first payment and the outstanding balance after the first payment. We can use this information to find the interest and principal portions of the second payment and the outstanding balance after the second payment, and then repeat the process for the third payment.
After the first payment, the outstanding balance is $9,856.67. We can find the interest portion of the second payment using the simple interest formula with \(P=9\,856.67\text{,}\)\(r=0.06\text{,}\) and \(t=\frac{1}{12}\text{.}\)
The result is summarized in the following amortization table.
Table3.2.8.Amortization Table
Payment Number
Payment
Interest
Principal
Balance
1
$193.33
$50.00
$143.33
$9,856.67
2
$193.33
$49.28
$144.05
$9,712.62
3
$193.33
$48.56
$144.77
$9,567.85
A spreadsheet program can be used to create an amortization table for the entire loan term, which can be very helpful for keeping track of the payments and the outstanding balance over time. Once the first few rows of the table are completed, you can use the fill-down feature to automatically fill in the rest of the table for the remaining payments. A sample amortization table 1
In the sample amortization table, the ending balance after 30 years was $2.69 rather than $0 because of rounding. The interest and principal portions are rounded to the nerest cent for each payment. In practice, the final payment would be adjusted to account for this rounding error so that the loan would be completely paid off at the end of the loan term.
Exercises3.2.4Exercises
1.
$1000 is invested at 5% simple interest for 3 years. How much interest will be earned? What will the value of the account be at maturity?
2.
$2,500 is invested at 4% simple interest for 2 years. How much interest will be earned? What will the value of the account be at maturity?
3.
You are borrowing $500 from a friend to be repaid in 6 months. If the annual interest rate is 5% simple interest, how much interest will you owe?
4.
You are borrowing $1,200 from a friend to be repaid in 9 months. If the annual interest rate is 8% simple interest, how much interest will you owe?
5.
Find the future value of $500 invested at 3% simple interest for 10 years.
6.
Find the future value of $1,200 invested at 6% simple interest for 5 years.
7.
Find the present value of $2,000 to be received in 4 years if the annual interest rate is 8% simple interest.
8.
Find the present value of $5,000 to be received in 3 years if the annual interest rate is 10% simple interest.
9.
If $200 is invested into an account that earns 4% simple interest, how long will it take for the value to double?
10.
A payday loan company charges $20 for a 10-day loan of $100. What is the annual interest rate on this loan, assuming simple interest? Round to the nearest hundredth of a percent.
11.
Find the interest and principal portions of the first payment on a 3-year amortized car loan of $15,000 with an annual interest rate of 5% and monthly payments of $449.22. Then find the outstanding balance after the first payment.
12.
Complete an amortization table for the first 3 payments on the car loan in the previous exercise.